cakephp2-php8/lib/Cake/View/JsonView.php
2011-11-27 23:51:48 -05:00

84 lines
2.5 KiB
PHP

<?php
/**
* CakePHP(tm) : Rapid Development Framework (http://cakephp.org)
* Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
*
* Licensed under The MIT License
* Redistributions of files must retain the above copyright notice.
*
* @copyright Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
* @link http://cakephp.org CakePHP(tm) Project
* @license MIT License (http://www.opensource.org/licenses/mit-license.php)
*/
App::uses('View', 'View');
/**
* A view class that is used for JSON responses.
*
* By setting the 'serialize' key in your controller, you can specify a view variable
* that should be serialized to JSON and used as the response for the request.
* This allows you to omit views + layouts, if your just need to emit a single view
* variable as the JSON response.
*
* In your controller, you could do the following:
*
* `$this->set(array('posts' => $posts, 'serialize' => 'posts'));`
*
* When the view is rendered, the `$posts` view variable will be serialized
* into JSON.
*
* If you don't use the `serialize` key, you will need a view + layout just like a
* normal view.
*
* @package Cake.View
* @since CakePHP(tm) v 2.1.0
*/
class JsonView extends View {
/**
* JSON views are always located in the 'json' sub directory for a
* controllers views.
*
* @var string
*/
public $subDir = 'json';
/**
* Constructor
*
* @param Controller $controller
*/
public function __construct($controller) {
if (is_object($controller)) {
foreach (array('viewVars', 'viewPath', 'view', 'response') as $var) {
$this->{$var} = $controller->{$var};
}
$this->response->type('json');
}
}
/**
* Render a JSON view.
*
* Uses the special 'serialize' parameter to convert a set of
* view variables into a JSON response. Makes generating simple
* JSON responses very easy. You can omit the 'serialize' parameter,
* and use a normal view + layout as well.
*
* @param string $view The view being rendered.
* @param string $layout The layout being rendered.
* @return string The rendered view.
*/
public function render($view = null, $layout = null) {
if (isset($this->viewVars['serialize'])) {
$serialize = $this->viewVars['serialize'];
$data = isset($this->viewVars[$serialize]) ? $this->viewVars[$serialize] : null;
return $this->output = json_encode($data);
}
if ($view !== false && $viewFileName = $this->_getViewFileName($view)) {
return $this->output = $this->_render($viewFileName);
}
}
}