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https://github.com/kamilwylegala/cakephp2-php8.git
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starting to refactor views.
Adding comments. Incomplete.
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parent
c64e41eb45
commit
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2 changed files with 43 additions and 20 deletions
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@ -1,9 +1,5 @@
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<?php
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/**
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* A custom view class that is used for JSON responses
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*
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* PHP 5
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*
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* CakePHP(tm) : Rapid Development Framework (http://cakephp.org)
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* Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
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*
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@ -12,17 +8,31 @@
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*
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* @copyright Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
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* @link http://cakephp.org CakePHP(tm) Project
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* @package Cake.View
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* @since CakePHP(tm) v 2.1.0
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* @license MIT License (http://www.opensource.org/licenses/mit-license.php)
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*/
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App::uses('View', 'View');
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/**
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* JsonView
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* A view class that is used for JSON responses.
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*
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* By setting the 'serialize' key in your controller, you can specify a view variable
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* that should be serialized to JSON and used as the response for the request.
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* This allows you to omit views + layouts, if your just need to emit a single view
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* variable as the JSON response.
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*
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* In your controller, you could do the following:
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*
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* `$this->set(array('posts' => $posts, 'serialize' => 'posts'));`
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*
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* When the view is rendered, the `$posts` view variable will be serialized
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* into JSON.
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*
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* If you don't use the `serialize` key, you will need a view + layout just like a
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* normal view.
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*
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* @package Cake.View
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* @since CakePHP(tm) v 2.1.0
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*/
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class JsonView extends View {
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@ -53,13 +63,14 @@ class JsonView extends View {
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* @return string The rendered view.
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*/
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public function render($view = null, $layout = null) {
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if ($view !== false && $viewFileName = $this->_getViewFileName($view)) {
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$this->_render($viewFileName);
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if (isset($this->viewVars['serialize'])) {
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$serialize = $this->viewVars['serialize'];
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$data = isset($this->viewVars[$serialize]) ? $this->viewVars[$serialize] : null;
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return $this->output = json_encode($data);
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}
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if ($view !== false && $viewFileName = $this->_getViewFileName($view)) {
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return $this->output = $this->_render($viewFileName);
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}
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$data = isset($this->viewVars['serialize']) ? $this->viewVars['serialize'] : null;
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return $this->output = json_encode($data);
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}
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}
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@ -1,9 +1,5 @@
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<?php
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/**
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* A custom view class that is used for XML responses
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*
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* PHP 5
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*
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* CakePHP(tm) : Rapid Development Framework (http://cakephp.org)
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* Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
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*
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@ -12,8 +8,6 @@
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*
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* @copyright Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
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* @link http://cakephp.org CakePHP(tm) Project
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* @package Cake.View
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* @since CakePHP(tm) v 2.1.0
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* @license MIT License (http://www.opensource.org/licenses/mit-license.php)
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*/
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@ -21,9 +15,27 @@ App::uses('View', 'View');
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App::uses('Xml', 'Utility');
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/**
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* XmlView
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* A view class that is used for creating XML responses.
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*
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* By setting the 'serialize' key in your controller, you can specify a view variable
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* that should be serialized to XML and used as the response for the request.
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* This allows you to omit views + layouts, if your just need to emit a single view
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* variable as the XML response.
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*
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* In your controller, you could do the following:
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*
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* `$this->set(array('posts' => $posts, 'serialize' => 'posts'));`
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*
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* When the view is rendered, the `$posts` view variable will be serialized
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* into XML.
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*
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* **Note** The view variable you specify must be compatible with Xml::fromArray().
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*
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* If you don't use the `serialize` key, you will need a view + layout just like a
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* normal view.
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*
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* @package Cake.View
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* @since CakePHP(tm) v 2.1.0
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*/
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class XmlView extends View {
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