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starting to refactor views.

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Adding comments.
Incomplete.
This commit is contained in:
mark_story 2011-11-06 22:13:35 -05:00
parent c64e41eb45
commit 011fd51539
2 changed files with 43 additions and 20 deletions
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37
lib/Cake/View/JsonView.php
View file

@ -1,9 +1,5 @@
<?php
/**
* A custom view class that is used for JSON responses
*
* PHP 5
*
* CakePHP(tm) : Rapid Development Framework (http://cakephp.org)
* Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
*
@ -12,17 +8,31 @@
*
* @copyright Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
* @link http://cakephp.org CakePHP(tm) Project
* @package Cake.View
* @since CakePHP(tm) v 2.1.0
* @license MIT License (http://www.opensource.org/licenses/mit-license.php)
*/
App::uses('View', 'View');
/**
* JsonView
* A view class that is used for JSON responses.
*
* By setting the 'serialize' key in your controller, you can specify a view variable
* that should be serialized to JSON and used as the response for the request.
* This allows you to omit views + layouts, if your just need to emit a single view
* variable as the JSON response.
*
* In your controller, you could do the following:
*
* `$this->set(array('posts' => $posts, 'serialize' => 'posts'));`
*
* When the view is rendered, the `$posts` view variable will be serialized
* into JSON.
*
* If you don't use the `serialize` key, you will need a view + layout just like a
* normal view.
*
* @package Cake.View
* @since CakePHP(tm) v 2.1.0
*/
class JsonView extends View {
@ -53,13 +63,14 @@ class JsonView extends View {
* @return string The rendered view.
*/
public function render($view = null, $layout = null) {
if ($view !== false && $viewFileName = $this->_getViewFileName($view)) {
$this->_render($viewFileName);
}
$data = isset($this->viewVars['serialize']) ? $this->viewVars['serialize'] : null;
if (isset($this->viewVars['serialize'])) {
$serialize = $this->viewVars['serialize'];
$data = isset($this->viewVars[$serialize]) ? $this->viewVars[$serialize] : null;
return $this->output = json_encode($data);
}
if ($view !== false && $viewFileName = $this->_getViewFileName($view)) {
return $this->output = $this->_render($viewFileName);
}
}
}

26
lib/Cake/View/XmlView.php
View file

@ -1,9 +1,5 @@
<?php
/**
* A custom view class that is used for XML responses
*
* PHP 5
*
* CakePHP(tm) : Rapid Development Framework (http://cakephp.org)
* Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
*
@ -12,8 +8,6 @@
*
* @copyright Copyright 2005-2011, Cake Software Foundation, Inc. (http://cakefoundation.org)
* @link http://cakephp.org CakePHP(tm) Project
* @package Cake.View
* @since CakePHP(tm) v 2.1.0
* @license MIT License (http://www.opensource.org/licenses/mit-license.php)
*/
@ -21,9 +15,27 @@ App::uses('View', 'View');
App::uses('Xml', 'Utility');
/**
* XmlView
* A view class that is used for creating XML responses.
*
* By setting the 'serialize' key in your controller, you can specify a view variable
* that should be serialized to XML and used as the response for the request.
* This allows you to omit views + layouts, if your just need to emit a single view
* variable as the XML response.
*
* In your controller, you could do the following:
*
* `$this->set(array('posts' => $posts, 'serialize' => 'posts'));`
*
* When the view is rendered, the `$posts` view variable will be serialized
* into XML.
*
* **Note** The view variable you specify must be compatible with Xml::fromArray().
*
* If you don't use the `serialize` key, you will need a view + layout just like a
* normal view.
*
* @package Cake.View
* @since CakePHP(tm) v 2.1.0
*/
class XmlView extends View {